Sunday, November 18, 2012
Robert Ghrist!
This is what turned me on to higher math. I had no idea these lectures were floating around the internet until today. Enjoy them!
Monday, October 8, 2012
Let's do some basic math problems!
On the strikeout: math is fun, and being handed problems you know how to solve is also fun. How long has it been since you did long division in your head? This isn't teaching me anything new, but it makes my mind feel more limber.
Wednesday, September 12, 2012
ABC Conjecture
Heard the news? It's a big deal if the proof goes through.
Shinichi Mochizuki recently released a 500-page proof (split up in four sections) that claims to have solved the ABC conjecture:
Apparently he needed to use non-well-founded sets to get this result. Neat stuff.
Paper 1 Paper 2 Paper 3 Paper 4
Updated to add better-educated folks' commentary on the paper:
Take one Take Two Take Three MathOverflow
Shinichi Mochizuki recently released a 500-page proof (split up in four sections) that claims to have solved the ABC conjecture:
$\, \forall \, \epsilon > 1 \, \exists \,$ only finitely many coprime $a, b$ such that $d^{\epsilon} < c$ where $c=a+b$ and $d$ is the product of the unique prime factors of $abc$ (the "square free" part).
Paper 1 Paper 2 Paper 3 Paper 4
Updated to add better-educated folks' commentary on the paper:
Take one Take Two Take Three MathOverflow
Wednesday, August 15, 2012
Real Analysis $\mathbb{R}$e-view
On going through a layperson-readable take on Skolem's paradox here I noticed that the author (Steven Landsburg) talked about producing different models of $\mathbb{R}$ from different 'models' of $\mathcal{P}(\mathbb{Q})$ (powersets of the rationals). Why didn't he talk about Cauchy sequences? (because that's how we construct $\mathbb{R}$, right?)
As long as we don't mind throwing out the really boring sequences (like $\{1,1,1,1...\}$) with only finitely many unique elements, no emphasis on sequences is necessary. Because $\mathbb{Q}$ is countable, any subset is at most countable, and can be ordered and considered as a sequence. Furthermore, actually assigning an ordering is unnecessary...
Call a subset $S \subset \mathbb{Q}$ a Cauchy subset iif
1) $S$ is infinite
2) $\, \forall \, \epsilon > 0 \, \exists \, x \in S$ such that $\{ y \in S : |x-y|\geq \epsilon \}$ is finite
As an exercise, show (because my probably-nonexistent readership loves exercises, right?)
-$S$ is a Cauchy sequence under a particular ordering $\Leftrightarrow$ $S$ is a Cauchy set $\Leftrightarrow$ $S$ is a Cauchy sequence under every ordering.
-All the above statements/definitions work equally well with subsets of $\mathbb{R}$, not just $\mathbb{Q}$. (hint: show that condition 2 forces $S$ to be at most countable)
As long as we don't mind throwing out the really boring sequences (like $\{1,1,1,1...\}$) with only finitely many unique elements, no emphasis on sequences is necessary. Because $\mathbb{Q}$ is countable, any subset is at most countable, and can be ordered and considered as a sequence. Furthermore, actually assigning an ordering is unnecessary...
Call a subset $S \subset \mathbb{Q}$ a Cauchy subset iif
1) $S$ is infinite
2) $\, \forall \, \epsilon > 0 \, \exists \, x \in S$ such that $\{ y \in S : |x-y|\geq \epsilon \}$ is finite
As an exercise, show (because my probably-nonexistent readership loves exercises, right?)
-$S$ is a Cauchy sequence under a particular ordering $\Leftrightarrow$ $S$ is a Cauchy set $\Leftrightarrow$ $S$ is a Cauchy sequence under every ordering.
-All the above statements/definitions work equally well with subsets of $\mathbb{R}$, not just $\mathbb{Q}$. (hint: show that condition 2 forces $S$ to be at most countable)
Sunday, May 13, 2012
(AG) Reading Rainbow: Get Your Books!
So there's an Algebraic Geometry reading group at this subreddit.
If you're up for this, it looks like you'll have to buy the Beltrametti et al book on your own. But if you're looking to pick up the other books, and maybe you also want to score an Introduction to Commutative Algebra with some solution manuals on the side... I know a guy... (the blogger gestures down a nearby alley)
Follow the link after the break...
If you're up for this, it looks like you'll have to buy the Beltrametti et al book on your own. But if you're looking to pick up the other books, and maybe you also want to score an Introduction to Commutative Algebra with some solution manuals on the side... I know a guy... (the blogger gestures down a nearby alley)
Follow the link after the break...
Labels:
declarations,
math,
news
Sunday, April 29, 2012
Provability < Proof
I haven't touched this blog in over a month.... time to post more!
While I'm fooling around with other stuff, enjoy something I learned in freenode's #math channel a few minutes ago (after the break, with names omitted)
While I'm fooling around with other stuff, enjoy something I learned in freenode's #math channel a few minutes ago (after the break, with names omitted)
Yet another reason to find Gödel's incompleteness theorems surprising
Thursday, March 15, 2012
Keepin' it Hyperreal
I haven't posted anything here in a while, so let's do something cool... like construct $^*\mathbb{R}$
Swag.
This will be more about the crazy set theory shenanigans that go into building $^*\mathbb{R}$, rather than actually working in $^*\mathbb{R}$... maybe I'll cover the practical side in another blogpost...
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